1. 毕业设计（论文）的内容和要求

结肠癌(colorectal cancer ,crc)是人类高发恶性肿瘤, 其发病率一直呈上升趋势, 在全球恶性肿瘤发病率中已上升至第三位, 其死亡率居恶性肿瘤死因的第二位。

在我国, 结直肠癌死亡率已位于恶性肿瘤死亡率的第五位, 严重危害人类健康。

与大多数肿瘤的治疗相同，结肠癌的治疗也主要是通过手术切除。

2. 参考文献

[1] Wang MJ, Wang ZQ, Wang R, Ping J, Zhou ZG, Sun XF. The elderly patients with colorectal cancer need careful multidisciplinary evaluation and optimizing comprehensive management. Int J Colorectal Dis. 2015. 30(5): 713-4. [2] Zheng ZX, Zheng RS, Zhang SW, Chen WQ. Colorectal cancer incidence and mortality in China, 2010. Asian Pac J Cancer Prev. 2014. 15(19): 8455-60. [3] McGuire S. World Cancer Report 2014. Geneva, Switzerland: World Health Organization, International Agency for Research on Cancer, WHO Press, 2015. Adv Nutr. 2016. 7(2): 418-9. [4] Alekshun MN, Levy SB. Molecular mechanisms of antibacterial multidrug resistance. Cell. 2007. 128(6): 1037-50. [5] Niehrs C. The complex world of WNT receptor signalling. Nat Rev Mol Cell Biol. 2012. 13(12): 767-79. [6] Clevers H, Nusse R. Wnt/β-catenin signaling and disease. Cell. 2012. 149(6): 1192-205. [7] Bienz M, Clevers H. Linking colorectal cancer to Wnt signaling. Cell. 2000. 103(2): 311-20. [8] Mao J, Wang D, Wang Z, et al. Combretastatin A-1 phosphate, a microtubule inhibitor, acts on both hepatocellular carcinoma cells and tumor-associated macrophages by inhibiting the Wnt/β-catenin pathway. Cancer Lett. 2016. 380(1): 134-43. [9] Wang Z, Li B, Zhou L, et al. Prodigiosin inhibits Wnt/β-catenin signaling and exerts anticancer activity in breast cancer cells. Proc Natl Acad Sci U S A. 2016. 113(46): 13150-13155. [10] Bilic J, Huang YL, Davidson G, et al. Wnt induces LRP6 signalosomes and promotes dishevelled-dependent LRP6 phosphorylation. Science. 2007. 316(5831): 1619-22. [11] Molenaar M, van de Wetering M, Oosterwegel M, et al. XTcf-3 transcription factor mediates beta-catenin-induced axis formation in Xenopus embryos. Cell. 1996. 86(3): 391-9.

3. 毕业设计（论文）进程安排

2月 确定毕业设计的课题及相关资料的查找 3月 完成相关的材料准备；完成开题报告 3月 实验方法的确定及实验条件的优化 4月 实验阶段 5月 各项指标作比较，实验数据处理 6月 毕业论文的书写 6月 在导师指导下修改论文，完成答辩